gson的@Expose注解和@SerializedName注解 serializedname

1.使用@Expose可以区分实体中不想被序列化的属性

1. publicclassUser{
3. @Expose
4. privateStringusername;
5. @Expose(serialize=false)
6. privateintage;
8. privateListlist;
10. publicUser(Stringusername,intage){
11. super();
12. this.username=username;
13. this.age=age;
14. }
16. publicStringgetUsername(){
17. returnusername;
18. }
19. publicvoidsetUsername(Stringusername){
20. this.username=username;
21. }
22. publicintgetAge(){
23. returnage;
24. }
25. publicvoidsetAge(intage){
26. this.age=age;
27. }
28. publicListgetList(){
29. returnlist;
30. }
31. publicvoidsetList(Listlist){
32. this.list=list;
33. }
35. publicstaticvoidmain(String[]args){
36. Useruser=newUser("lemon",27);
37. Listlist=newArrayList();
38. list.add("l1");
39. list.add("l2");
40. user.setList(list);
41. Gsong1=newGson();
42. //使用newGson();
43. System.out.println(g1.toJson(user));//{"username":"lemon","age":27,"list":["l1","l2"]}
44. //使用newGsonBuilder().excludeFieldsWithoutExposeAnnotation().create();
45. Gsong2=newGsonBuilder().excludeFieldsWithoutExposeAnnotation().create();
46. System.out.println(g2.toJson(user));//{"username":"lemon"}
47. }
48. }

@Expose

@SerializedName("name")

privateStringusername;

publicstaticvoidmain(String[]args){

Useruser=newUser("lemon",27);

Listlist=newArrayList();

list.add("l1");

list.add("l2");

user.setList(list);

Gsong1=newGson();

//使用newGson();

//{"name":"lemon","age":27,"list":["l1","l2"]}

System.out.println(g1.toJson(user));

//使用newGsonBuilder().excludeFieldsWithoutExposeAnnotation().create();

Gsong2=newGsonBuilder().excludeFieldsWithoutExposeAnnotation().create();

//{"name":"lemon"}

System.out.println(g2.toJson(user));

}

补充：简单方式：排除部分不序列化的属性（特别是循环引用的）可以使用关键字：transient。

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